Question 681977
Transform the point-slope form to slope intercept for
y-3=2(x-1)
y-3=2x-2
y =2x-2+3
y=2x + 1
y intercept is 1, plot (0,1)
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x intercept is where y = 0
0=2x+1
-1 = 2x
x = {{{-1/2}}}, plot ({{{-1/2}}},0)
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From the point slope plot the point (1,3)
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Draw a line through the point and the intercept
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{{{graph(300,200,-10,10,-10,10,2x+1)}}}
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y-5=(-1/4)x+2
y = (-1/4)x+2+5
y = (-1/4)x + 7
y intercept is 7, plot (0,7)
x intercept is where y = 0
0 = (-1/4)x + 7
-7 = (-1/4)x
28 = x, plot (28,0)
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Taking y-5 = (-1/4)x+2 backward into point-slope
y-5 = (-1/4)(x + -8)
Plot the intercepts and the point (8,5) and draw a line through them.
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{{{graph(300,200,-10,30,-10,10,(-1/4)x+7)}}}
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