Question 61448
to solve this problem you must se up an equation as {{{ (x2-x1) / (y2-y1) }}}  in this case it would be {{{ (-2-1)/(5-3)}}}  It gives you {{{ -3/2 }}}  which makes your slope of 1,3 and -2,5 {{{3/2}}}  The slope of a parallel line is always the same which would make it {{{3/2}}} as well. If it were a perpandicular line it would be the negitive inverse of that, making it {{{-2/3}}}