Question 681935
f(x)= 3*pi^(3-x) + logpi 3
<pre>
I can't tell whether that is

{{{"f(x)"}}}{{{""=""}}}{{{3*pi^(3-x) + log((pi^3))}}}

or

{{{"f(x)"}}}{{{""=""}}}{{{3*pi^(3-x) + (log(pi))^3)}}}

In either case the first term {{{3*pi^(3-x)}}} approaches 
(gets very close to 0 as x get's very large.  So the
lowest value of f(x) will get closer and closer to the
value of the 2nd term. There is no limit of the highest
value of f(x), so the range in interval notation is: 

{{{(matrix(1,3,

log((pi^3)), ",",infinity))}}} if {{{"f(x)"}}}{{{""=""}}}{{{3*pi^(3-x) + log((pi^3))}}}

or

{{{(matrix(1,3,

(log(pi))^3, ",",infinity))}}} if {{{"f(x)"}}}{{{""=""}}}{{{3*pi^(3-x) + (log(pi))^3)}}}

Edwin</pre>