<PRE><B>Question 681797</B>
A motor boat leaves the harbor traveling at 10 mph. Three hours later a cabin cruiser leaves the harbor traveling at 30 mph. In how many hours after the cabin cruiser leaves will it be along side the motor boat?
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Motor Boat DATA:
rate = 10 mph ; time = x + 3 hrs ; distance = 10(x+3) miles
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Cruiser DATA:
rate = 30 mph ; time = x hrs ; distance = 30x miles
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Equation:
distance = distance
10x + 30 = 30x
20x = 30
x = 3/2 hrs. (time to catch the motor boat)
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Cheers,
Stan H.
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