Question 681776
For the function f(x) represented as y=x^2-4.
A) How do I write the equation defining the inverse of f(x)
1st: Interchange x and y to get:
x = y^2-4
2nd: Solve for "y":
y^2 = x+4
y = +-sqrt(x+4)
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B) How do I sketch the graphs of f and its inverse relation on the same axes?
{{{graph(400,400,-10,10,-10,10,x^2-4,(x+4)^(1/2),-(x+4)^(1/2))}}}
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C) How do I state whether the inverse relation is a function?
It is not because there are x values in the domain of f^-1(x) that
have 2 associated y-values.
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Cheers,
Stan H.