Question 681560
you will find the {{{x}}} and {{{y}}} intercept of {{{4x=7y+9}}} if you set {{{x=0}}} and solve for {{{y}}}, then set {{{y=0}}} and solve for {{{x}}}

if {{{x=0}}}

{{{4*0=7y+9}}}

{{{0=7y+9}}}

{{{-9=7y}}}

{{{-9/7=y}}}

or

{{{-1.29=y}}}.....so, the {{{y}}} intercept is at ({{{0}}},{{{-1.29}}})


if {{{y=0}}}

{{{4x=7*0+9}}}

{{{4x=0+9}}}

{{{4x=9}}}

{{{x=9/4}}}

or

{{{x=2.25}}}.......and the {{{x}}} intercept is at ({{{2.25}}},{{{0}}})


let's check it on a graph

{{{drawing(600,600,-10,10,-10,10,grid(0),circle(0,-1.29,0.15),circle(2.25,0,0.15),graph(600,600,-10,10,-10,10,(4/7)x-9/7))}}}