Question 681382
Arrange into y=mx+b format
...
-1x + 3y - 8 = 0
Isolate the y variable
3y = x + 8
y = {{{(1/3)x + 8/3}}}
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slope, m, is {{{1/3}}}
y intercept, b, is {{{8/3}}} plot as (0, {{{8/3}}})
x intercept is where y = 0 
0 = {{{(1/3)x + 8/3}}}}
{{{-8/3 = (1/3)x}}}
{{{x = (-8/3)(3) = -8}}}
so, x intercept is (-8, 0)
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{{{graph(300,200,-10,10,-10,10,(1/3)x+(8/3))}}}
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