Question 681222
The sum of four times a number and 1 is equal to the difference of twice the number and 2. Find the number. 

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times means *
sum means +
equal means =
twice means 2*
difference means -
Let a number be n
Then your algebraic equation to solve is:
{{{4n+1=2n-2}}}
{{{-2n+4n+1=-2n+2n-2}}}
{{{2n+1=-2}}}
{{{2n+1-1=-2-1}}}
{{{2n=-3}}}
{{{2n/2=-3/2}}}
{{{highlight(n=-3/2)}}}

Hope that helped.  Happy Calculating!!!