Question 681162
which point is further from the origin p(8,1) q(6,4)
<br>The origin is (0,0)<br>
The distance formula is {{{d=sqrt((x2-x1)^2+(y2-y1)^2)}}}
for p:
{{{d=sqrt((8-0)^2+(1-0)^2)}}}
{{{d=sqrt(64+1)}}}
{{{d=sqrt(65)}}}
for q:
{{{d=sqrt((6-0)^2+(4-0)^2)}}}
{{{d=sqrt(36+16)}}}
{{{d=sqrt(52)}}}

<br> p is further away from the origin than q. <br>

Hope that helped.  Happy Calculating!!!