Question 61400
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{{{(ab/m)(-2m^(-2)/ba + 3m/(a^(-1b)))}}}
{{{(ab/m)(-2/(m^2*ba)+3ma/b)}}}
{{{(ab/m)(-2/(m^2*ba))+(ab/m)(3ma/b)}}}
{{{-2ab/(abm^3)+3a^2*bm/bm)}}}  Cancel terms that match top to bottom.
{{{-2/m^3+3a^2}}}
Happy Calculating!!!