Question 680789
4x^2+x-3=0
compare with ax^2+bx+c=0
Find the roots of the equation by quadratic formula				
a=	4	b=	1	c=	-3		
							
b^2-4ac=	1	-	-48				
b^2-4ac=	49			{{{sqrt(	49	)}}}=	7
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}							
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}							
x1=(	-1	+	7	)/	8		
x1=	0.75						
x2=(	-1	-7	) /	8			
x2=	-1				
The roots are  0.75,-1