Question 680570
Subtract the equations to cancel out x and solve for y
x - 2y = 8
x + y = 2
...
x - x - 2y - y = 8 - 2
-3y = 6
y = -2
...
Multiply the second equation by 2 and add to the first equation
x-2y=8
2x+2y=4
x + 2x - 2y + 2y = 8 + 4
3x = 12
x = 4
...
{{{highlight_green(x=4)}}} and {{{highlight_green(y=-2)}}}
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