Question 680266
5 log2 (2 x – 3) = log2 (2 x – 3) + 12, what is the value of x?
5 log2 (2 x – 3) - log2 (2 x – 3) = 12
4 log2 (2 x – 3)= 12
log2 (2 x – 3)=3
2^3=2x-3
8=2x-3
2x=11
x=11/2=5.5