Question 680502
Use the quadratic formula to solve for x


{{{x = (-b+-sqrt(b^2-4ac))/(2a)}}}


{{{x = (0+-sqrt((0)^2-4(9)(-28)))/(2(9))}}} Plug in {{{a = 9}}}, {{{b = 0}}}, {{{c = -28}}}


{{{x = (""+-sqrt(0-(-1008)))/(18)}}}


{{{x = (""+-sqrt(0+1008))/(18)}}}


{{{x = (""+-sqrt(1008))/18}}}


{{{x = (sqrt(1008))/18}}} or {{{x = (-sqrt(1008))/18}}}


{{{x = (12*sqrt(7))/18}}} or {{{x = (-12*sqrt(7))/18}}}


<font color="red">Exact Solutions:</font> {{{x = (2*sqrt(7))/3}}} or {{{x = (-2*sqrt(7))/3}}}


<font color="blue">Approximate Solutions:</font> {{{x = 1.763834}}} or {{{x = -1.763834}}}