Question 680462
Jennifer leaves her house going 25 mph. Her mom leaves 20 minutes later, going 90 mph. When will Mom catch up with Jennifer?
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Jennifer DATA:
rate = 25 mph ; time = x hrs ; distance = 25x miles
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Mom DATA:
rate = 90 mph ; time = (x-(1/3)) hrs ; distance = 90x-30 miles
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Equation:
distance = distance
25x = 90x-30
65x = 30
x = 6/13 hrs = (6/13)*60 = 27.69 = 27 min 42 seconds
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Cheers,
Stan H.
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