Question 680445
{(x^2-25)/(5y)} / {(5-x)/(20xy)}
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Note that (x-5)/(5-x) = -1
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{(x-5)(x+5)/5y} / {(5-x)/20xy}
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= [(-1)(x+5)/5y] / [1/20xy]
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Invert the denominator and multiply:
= [-(x+5)/5y]*[20xy]
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= -(x+5)(4x)
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= -4x^2-20x
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Cheers,
Stan H.
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