Question 680378
Solve the system by the elimination method. 
2a + 3b = 6 
5a + 2b - 4 = 0 
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multiply thru the top equation by 2
Multiply thru the bottom equation by 3
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4a + 6b = 12
15a+ 6b = 12
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Subtract and solve for "a":
11a = 0
a = 0
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Solve for "b" using 2a + 3b = 6
2*0 + 3b = 6
b = 2
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Cheers,
Stan H.
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