Question 680309
Can you tell me if I have done this correctly?  For the function f(x)=(3-4x)^2, find f^-1.  Determine whether f^-1 is a function.
sq rt.y=3-4x
sq rt y^-3=-4x ****** The ^ is unnecessary and confusing ****
x=(sq rt y^-3)/-4
f^-1(x)=sq rt y^-3/-4  and it is not a function.  Thanks
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f(x)=(3-4x)^2
y = (3-4x)^2
--> x = (3-4y)^2
3-4y = sqrt(x)
y = (3 - sqrt(x))/4  Same as your answer.

Not a function.