Question 679914


{{{20-z/3=z/2}}}...here you have whole number {{{20}}} and fractions {{{-z/3}}} and {{{z/2}}}; so, you need to get a rid of fractions and have all whole numbers
in order to do that, you need to multiply both sides with LCD for {{{2}}} and {{{3}}} which is {{{6}}}

{{{20*6-(z/3)6=(z/2)6}}}

{{{120-(z/cross(3))cross(6)2=(z/cross(2))cross(6)3}}}

{{{120-2z=3z}}}

{{{120=3z+2z}}}

{{{120=5z}}}

{{{120/5=z}}}

{{{24=z}}}