Question 679793
simplifying problems like (3x^2)^3(-2x^3)^5,
:
When raising a power, to another power, you multiply the exponents
distribute the outside exponents, inside the brackets
{{{(3^3*x^(2*3))}}} * {{{(-2^5*x^(3*2))}}}
 (raising a neg number by an odd exponent always results in a negative)
{{{(27*x^6)}}} * {{{(-32*x^15)}}}
combine like terms, add exponents when you multiply
{{{27*-32*x^(6+15)}}}
{{{-864*x^21}}}
:
:
{{{(t^(2/7))^2}}} = {{{t^((2/7)*2)}}} = {{{t^(4/7)}}}, (the exponent is 4/7)