<PRE><B>Question 679765</B>
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Your answer key is wrong.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{(5\ -\ 6i)(4\ +\ 7i)}{(2\ +\ i)(5\ -\ 6i)}]


Note the common factor in numerator and denominator:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{4\ +\ 7i}{2\ +\ i}]


Now multiply by the conjugate of the denominator multiplied by itself.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(\frac{4\ +\ 7i}{2\ +\ i}\right)\left(\frac{2\ -\ i}{2\ -\ i}\right)\ =\ \frac{15\ +\ 10i}{5}\ =\ 3\ +\ 2i]



John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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