Question 679665

log[5](x + 1) - log[5](x - 1) = 2
log[5](x + 1)/(x - 1) = 2
(x + 1)/(x - 1) = 5^2
(x + 1)/(x - 1) = 25
(x + 1) = 25(x - 1)
x + 1 = 25x - 25
1 = 24x - 25
26 = 24x
26/24 = x
13/12 = x