Question 61334
In 28 years, a country's population doubled.  Write this equation exponentially
{{{2P=Pe^(k*28)}}}
{{{2P/P=Pe^(28k)/P}}}
{{{2=e^(28k)}}}
{{{ln(2)=ln(e^(28k))}}}
{{{ln(2)=28k*ln(e)}}}
{{{ln(2)=28k(1)}}}
{{{ln(2)=28k}}}
{{{ln(2)/28=28k/28}}}
{{{ln(2)/28=k}}}
:
{{{P(t)=Pe^(ln(2)t/28)}}}
:
You can approximate k if your teacher would rather:
{{{k=ln(2)/28}}}
{{{k=.0247552564}}}  Round it off to whatever your teacher wants:

{{{P(t)=Pe^(.0247552564t)}}}
Happy Calculating!!!