Question 61234
write it in standard form (Ax+By=C).

this is what i have done so far.

1.(-4,1);(-2,-1)
I can't follow what you've done, so I'm going to start from scratch.  I assume that you have been given these two points and are being asked for the equation of the line in standard form.
In order to write the equation of a line, you need a point and a slope.  So we need a slope.
To find the slope when given two points, we use the slope formula:{{{highlight(m=(y2-y1)/(x2-x1))}}}, m=slope, (x1,y1) and (x2,y2) are the given points.
(x1,y1)=(-4,1)  and (x2,y2)=(-2,-1)
{{{m=(-1-1)/(-2-(-4))}}}
{{{m=-2/(-2+4)}}}
{{{m=-2/2}}}
{{{m=-1}}}
Now we can use the point-slope formula to find the equation of the line:{{{highlight(y-y1=m(x-x1))}}}, m=slope and (x1,y1) is a given point.
m=-1 and (x1,y1)=(-4,1)
{{{y-1=-1(x-(-4))}}}
{{{y-1=-1(x+4)}}}
{{{y-1=-x-4}}}
{{{x+y-1=x-x-4}}}
{{{x+y-1=-4}}}
{{{x+y-1+1=-4+1}}}
{{{highlight(x+y=-3)}}}