Question 679336
Starting with {{{y = (2/3)x - 6}}}
slope is {{{2/3}}}
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Perpendicular lines have negative inverse (reciprocal) slopes
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slope of the perpendicular line will be {{{-3/2}}}
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y = {{{-3/2}}}x + b
Take the y intercept of the first line, (0,-6) as the point of intersection
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{{{highlight_green(y = (-3/2)x - 6)}}}
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{{{graph(300,200,-10,10,-10,1,(2/3)x-6,(-3/2)x-6)}}}
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