Question 679303
{{{(-3/cross(2))(cross(2)) = -3}}}
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{{{(5-2)/(2-4) = 3/-2 = -3/2}}}
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y - 5 = {{{-3/2}}}(x-2)
y - 5 = {{{(-3/2)x + 3}}}
y = {{{(-3/2)x + 3 + 5}}}
{{{highlight_green(y = (-3/2)x + 8)}}}
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