Question 679200
{{{(4x^4-4x^2+6x)/(x-4)}}}
...
x-4 goes into {{{4x^4-4x^2}}}: {{{4x^3}}}
to get
{{{4x^4-16x^3}}}
subtracting
{{{4x^4 - 4x^4 - 4x^2 - -16x^3}}}
yielding
{{{16x^3 - 4x^2}}}
...
x-4 goes into {{{16x^3-4x^2+6x}}}: {{{16x^2}}}
to get
{{{16x^3-64x^2}}}
subtracting
{{{16x^3 - 16x^3 - 4x^2 - -64x^2 + 6x}}}
yielding
{{{60x^2+6x}}}
...
{{{(4x^4-4x^2+6x)/(x-4) = q(x) = 4x^3 + 16x^2}}} remainder, r(x) =  {{{60x^2+6x}}}
...
{{{4x^3+16x^2}}}{{{(60x^2+6x)/(x-4)}}}
.....................
Delighted to help; feel free to email if you have further questions.
HomeworkHelpers@readingboosters.com
-Reading Boosters
Website: www.MyHomeworkAnswers.com 
Wanting for others what we want for ourselves.