Question 61318
The formula for factoring the difference of cubes is: {{{highlight(a^3-b^3=(a-b)(a^2+ab+b^2))}}}
{{{(p^3-1)/(p-1)}}}  Factor the difference of cubes on top, a=p and b=1.
{{{(p^3-1^3)/(p-1)}}}
{{{(p-1)(p^2+p(1)+1^2)/(p-1)}}}
{{{(p-1)(p^2+p+1)/(p-1)}}}
{{{cross((p-1))(p^2+p+1)/cross((p-1))}}}
{{{highlight(p^2+p+1)}}}
Happy Calculating!!!