<PRE><B>Question 679157</B>
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If the average of *[tex \LARGE n] numbers is *[tex \LARGE \overline{x}], then the sum of the *[tex \LARGE n] numbers must be *[tex \LARGE n\overline{x}].


So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3x\ +\ 56\ +\ 58\ =\ 5\,\cdot\,52]


Solve for *[tex \LARGE x]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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