Question 678908
{{{tan^3 (x) = 3 tan (x)}}}
{{{tan^3 (x) - 3 tan (x) = 0}}}
{{{tan(x)(tan^2 (x) - 3) = 0}}}
{{{tan(x) = 0}}} or {{{tan^2 (x) - 3 = 0}}}
{{{tan(x) = 0}}} or {{{tan^2 (x) = 3}}}
{{{tan(x) = 0}}} or {{{tan(x) = sqrt(3)}}} or {{{tan(x) = -sqrt(3)}}}<br>
From {{{tan(x) = 0}}} we get:
{{{x = 0 + 2pi*n}}}
{{{x = pi + 2pi*n}}}
From {{{tan(x) = sqrt(3)}}} we get:
{{{x = pi/3 + 2pi*n}}}
{{{x = 4pi/3 + 2pi*n}}}
From {{{tan(x) = -sqrt(3)}}} we get:
{{{x = -pi/3 + 2pi*n}}}
{{{x = 2pi/3 + 2pi*n}}}<br>
These six equations represent the general solution. (IOW <i>all</i> the possible solutions to your equation.) The n's in these equations integers. Replacing the n's with various integers will give you various x's that are solutions to your equation. I'll leave it up to you to try different n's to find the x's that are in the interval [0, {{{2pi}}}) (Hint: Each equation will provide only one x value that is in the interval.)