Question 679127
{{{x+y = 2}}}
{{{x = 14+3y}}}

Rearrange the second equation:

{{{x+y=2}}}
{{{x-3y = 14}}}

Subtract second equation from the first one:

{{{4y = -12}}}

{{{y = -3}}}

{{{x = 14+3(-3) = 5}}}

Thus solution {{{x=5}}} and {{{y=-3}}}.