Question 679051
{{{(y-8)/(y^2-9y-22)}}}
...
denominator cannot be 0
{{{y^2-9y-22 = 0}}}
(y-11)(y+2)=0
y-11=0, so y = 11
AND
y+2=0, so y=-2
...
Domain is all real numbers except -2 and 11
(-{{{infinity}}}, -2)U(-2,11)U(11, {{{infinity}}})
...
{{{graph(300,200,-20,20,-10,10,((x-8)/(x^2-9x-22)))}}}
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