Question 678903


{{{(5r-2)(6r-4)}}} Start with the given expression.



Now let's FOIL the expression.



Remember, when you FOIL an expression, you follow this procedure:



{{{(highlight(5r)-2)(highlight(6r)-4)}}} Multiply the <font color="red">F</font>irst terms:{{{(5*r)*(6*r)=30*r^2}}}.



{{{(highlight(5r)-2)(6r+highlight(-4))}}} Multiply the <font color="red">O</font>uter terms:{{{(5*r)*(-4)=-20*r}}}.



{{{(5r+highlight(-2))(highlight(6r)-4)}}} Multiply the <font color="red">I</font>nner terms:{{{(-2)*(6*r)=-12*r}}}.



{{{(5r+highlight(-2))(6r+highlight(-4))}}} Multiply the <font color="red">L</font>ast terms:{{{(-2)*(-4)=8}}}.



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So we have the terms: {{{30*r^2}}}, {{{-20*r}}}, {{{-12*r}}}, {{{8}}} 



{{{30*r^2-20*r-12*r+8}}} Now add every term listed above to make a single expression.



{{{30r^2-32r+8}}} Now combine like terms.



So {{{(5r-2)(6r-4)}}} FOILs to {{{30r^2-32r+8}}}.



In other words, {{{(5r-2)(6r-4)=30r^2-32r+8}}}.