Question 678815
Using y=2x+3, the slope is {{{2}}}
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A perpendicular line will have the negative inverse (reciporcal) slope of {{{-1/2}}}
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Using the point (-2,-4) and the determined slope, plug into the point-slope formula.
y - -4 = {{{-1/2}}}(x--2)
y + 4 = {{{-1/2}}}(x+2)
y + 4 = {{{(-1/2)x - (1/2)(2)}}}
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y = {{{(-1/2)x - 1-4}}}
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{{{highlight_green(y=(-1/2)x-5)}}}
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