Question 678787
{{{(6x^4-3x^5+2x^3+x-3)/(x+1) = (-3x^5+6x^4+2x^3+x-3)/(x+1)}}}
...
(x+1) goes into {{{-3x^5+6x^4}}}: {{{-3x^4}}}
to get
{{{-3x^5 - 3x^5}}}
subtracting
{{{-3x^5 - -3x^5 + 6x^4 -  -3x^4}}}
yielding
{{{9x^4}}}
...
(x+1) goes into {{{9x^4+2x^3}}}: {{{9x^3}}}
to get
{{{9x^4 + 9x^3}}}
subtracting
{{{9x^4 - 9x^4 + 2x^3 - 9x^3}}}
yielding
{{{-7x^3}}}
...
(x+1) goes into {{{-7x^3+x}}} : {{{-7x^2}}}
to get
{{{-7x^3 - 7x^2}}}
subtracting
{{{-7x^3 - -7x^3 + x - 7x^2}}}
yielding
x - 7x^2
...
(x+1) goes into {{{-7x^2 + x - 3}}}: {{{-7x}}}
to get 
{{{-7x^2 - 7x}}}
subtracting
{{{-7x^2 - -7x^2 + x - -7x - 3}}}
yielding
{{{8x-3}}}
...
The remainder is 8x-3
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