Question 657400
{{{(-2a^0)/((2a^-4)a) = (-2a^0)/((2a)/a^4)}}}
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{{{(-2(1))/(2a/a^4) = (-2)((a^4)/2a) = -2a^4/2a = -a^3}}}
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Alternatively,
{{{(-2a^0)/((2a^-4)a) = (-2a^0)/(2a^(-4+1))}}}
{{{(-2(1))/2a^-3 = -1/a^-3 = -1/(1/a^3) = -1(a^3/1) = -a^3}}}
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