Question 675461
{{{12x^6y^5}}} and {{{4x^4y^5}}}
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Both coefficients, 12 and 4, are divisible by 4
Each as multiple x and y variables, so factor out the one with the least of each variable, which is {{{x^4}}} and the full {{{y^5}}}
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{{{4x^4y^5(3x^2)}}} and {{{4x^4y^5(1)}}}
 
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