Question 61271
The area of the square is {{{s^2}}}.

The area of a circle = {{{pi*r^2}}}.
The area of a semicircle = {{{(pi*r^2)/2}}}.
In this case the radius of the semicircle = {{{s/2}}}.

So, the area of the semicircle = {{{pi*((s/2)^2)/2}}}.
This simplifies to {{{pi*s^2/8}}}.

So, the area of the square plus the semicircle = {{{s^2+pi*s^2/8}}}.