Question 678541
Use 2x+3y=6
3y = -2x + 6
y = {{{(-2/3)x+(6/3)}}}
y = {{{(-2/3)x+2}}}
y intercept is 2
Plot (0,2)
x intercept is where x = 0 
0 = {{{(-2/3)x+2}}}
-2 = {{{(-2/3)x}}}
{{{(-2)(-3/2) = x}}}
x = 3
Plot (3,0)
Draw a line through the intercepts
...
Use y = {{{2/3}}}x - 2
y intercept is -2
Plot(0,-2)
x intercept is where y = 0
0 = {{{(2/3)x - 2}}}
2 = {{{(2/3)x}}}
{{{(2)(3/2)}}} = x
x = 3
Plot (3,0)
Draw a line through the intercepts
...
Where the lines intersect is the solution point.
...
{{{graph(300,200,-10,10,-10,10, (-2/3)x+2, (2/3)x-2)}}}
...
To check algebraically,
{{{(-2/3)x+2 = (2/3)x-2}}}
{{{(-2/3)x - (2/3)x = -2 - 2}}}
{{{(-4/3)x = -4}}}
{{{x = -4(-3/4)}}}
{{{x = 3}}}
plut the x equals 3 into either of the linear equations and solve for y
y = {{{(2/3)(3) - 2}}}
y = 0
(3,0) is the solution
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