Question 678292
Starting with 3x + -2y = 2
Isolate the y
3x + - 2y + 2y = 2 + 2y
3x = 2 + 2y
3x - 2 = 2 + 2y - 2
3x - 2 = 2y
Divide the entire equation by 2
y = {{{(3/2)x - 2/2}}}
{{{highlight(y = (3/2)x-1)}}}
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Starting with -2x + y = 8
-2x + y + 2x = 8 + 2x
{{{highlight_green(y=2x+8)}}}
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Setting the quations equal,
{{{(3/2)x - 1 = 2x + 8}}}
Multiply the entire equation by 2
3x - 2 = 4x + 16
Isolate the x on one side of the equation
3x - 2 - 3x - 16 = 4x + 16 - 16 - 3x
-18 = x
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Using x equals -18, solve for y in either of the equations
y = 2(-18)+8 = -36 + 8 = -28
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(-18, -28)
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{{{graph(300,200,-20,1,-30,1,(3/2)x-1, 2x+8)}}}
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