Question 678402
{{{6z^2=z+2}}}

{{{6z^2-z=2}}}

/6
{{{z^2-(z/6) = 1/3}}}

Find the last term of perfect square

Last term = 1/2 the coefficient of 2nd. term squared

(1/2*1/6)^2

(1/12)^2= 1/144

add (1/44) to both sides

{{{z^2-(z/6) +(1/144) = (1/3) +(1/144)}}}

{{{(z+(1/12))^2= (48+1)/144 }}} ( taking the LCD

{{{(z+(1/12))^2= 49/144 }}}

Take the square root of both sides

(z+(1/12)) = +/- (7/12)

z= -(1/12) +(7/12) --->1/2

OR

z= -(1/12) -(7/12) ---> -2/3