Question 678402
{{{6z^2-z=2}}}
divide the netire equation by 6
{{{z^2 - (1/6)z = 1/3}}}
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{{{z^2 - (1/6)z+((1/2)(1/6))^2= (1/3) + ((1/2)(1/6))^2}}}
{{{z^2 - (1/6)z + 1/144 = (1/3) + (1/144)}}}
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{{{z^2 - (1/6)z + 1/144 = 49/144}}}
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{{{(z-(1/12))^2 = (49/144)}}}
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{{{sqrt(z -(1/12))^2}}} = +/- {{{sqrt(49/144)}}}
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z - {{{1/12}}} = +/- {{{7/12}}}
z = {{{(1/12) +- (7/12)}}}
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{{{highlight_green(z = 8/12 = 2/3)}}}
AND
{{{highlight_green(z =-6/12 = -1/2)}}}
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