Question 678403
6z^2=z+2
6z^2-z-2=0
{{{z = (-(-1) +- sqrt( (-1)^2-4*6*(-2) ))/(2*6) }}} 
z=1+- sqrt( 1+48 )/12
z=1 +- sqrt (49)/12
z= 1 +- 7/12
z= (12 +- 7)/12
z= (19/12), (5/12)