Question 678187
Assume the problem is:
{{{(4x-4)/(8x-8)}}} divided by {{{1/(3x)}}}
Factor the 1st fraction
{{{(4(x-1))/(8(x-1))}}} divided by {{{1/(3x)}}}
(x-1)'s cancel, reduce the fraction, invert the dividing fraction and multiply
{{{1/2}}} * {{{(3x)/1}}} = {{{(3x)/2}}}