<PRE><B>Question 678253</B>
Given the mean is 70 and the standard deviation is 8. Find the largest fraction of the numbers that could meet less than 50 or more than 90. 
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z(50) = (50-70)/8 = -20/8 = -5/2
z(90) = (90-70)/8 = +5/2
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Using Chebyshev:
P(50&lt;= x &lt;=90) is at least (1-(2/5)^2) = 0.84 = 84%
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Cheers,
Stan H.
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