Question 678264
{{{2sqrt(2)sin(q) + 2 = 0}}}

{{{2sqrt(2)sin(q) = -2}}}

{{{sin(q) = -1/sqrt(2) = -sqrt(2)/2}}}

Sine function is negative in quadrants III and IV. {{{sqrt(2)/2}}} corresponds to an angle of 45 degrees (or {{{pi/4}}}) in quadrant I.

Thus {{{q[III] = 5pi/4}}} in quadrant III, and {{{q[IV] = 7pi/4}}} in quadrant IV.