<PRE><B>Question 677680</B>
2x^3 + x^2 = 6x


2x^3 + x^2 - 6x = 0


x(2x^2 + x - 6) = 0


x(x + 2)(2x - 3) = 0


x = 0 or x + 2 = 0 or 2x - 3 = 0


x = 0 or x = -2 or 2x = 3


x = 0 or x = -2 or x = 3/2


So the three solutions are x = 0 or x = -2 or x = 3/2


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