Question 677632
the circles are externally tangent to the other two.

the lines joining the centers of the circles forms an equilateral triangle with sides = 2* radius=40 cms & the area of the triangle= (sqrt3/4)*40^2=692.8 cm sqr

the two radii of the circle form a sector with angl 60 degree

the area of the 3 sectors=3*(60/360)(pi radius^2) =3/6*22/7*20^2=628.57 cm sqr

the area contained between three circles of radius 
=the area of the triangle-the area of the 3 sectors
=692.8-628.57=64.23cm sqr
ans