Question 677516
2x^2+12=x^2+8x


2x^2+12-x^2-8x = 0


x^2-8x+12 = 0


(x-6)(x-2) = 0


x-6 = 0 or x-2 = 0


x = 6 or x = 2


So the solutions are x = 6 or x = 2