Question 677445
x x+1 x+2 x+3
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3(x+3) = (x+x+1+x+2)+6
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3x + 9 = (3x+3) + 6
3x + 9 = 3x + 3 + 6
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3x + * = 3x + 9
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0 = 0
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All  numbers are a solution.  Any four consecutive intergers.
For example,
1,2,3,4
3(4) = (1+2+3)+6
12 = 12
...
Another example
25,26,27,28
3(28) = (25+26+27) + 6
84 = 78 + 6
84 = 84

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